Integrand size = 25, antiderivative size = 88 \[ \int \frac {1}{(a-i a x)^{9/4} (a+i a x)^{9/4}} \, dx=\frac {2 x}{5 a^4 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x} \left (1+x^2\right )}+\frac {6 \sqrt [4]{1+x^2} E\left (\left .\frac {\arctan (x)}{2}\right |2\right )}{5 a^4 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \]
[Out]
Time = 0.01 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.160, Rules used = {42, 205, 203, 202} \[ \int \frac {1}{(a-i a x)^{9/4} (a+i a x)^{9/4}} \, dx=\frac {6 \sqrt [4]{x^2+1} E\left (\left .\frac {\arctan (x)}{2}\right |2\right )}{5 a^4 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}}+\frac {2 x}{5 a^4 \left (x^2+1\right ) \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \]
[In]
[Out]
Rule 42
Rule 202
Rule 203
Rule 205
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt [4]{a^2+a^2 x^2} \int \frac {1}{\left (a^2+a^2 x^2\right )^{9/4}} \, dx}{\sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \\ & = \frac {2 x}{5 a^4 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x} \left (1+x^2\right )}+\frac {\left (3 \sqrt [4]{a^2+a^2 x^2}\right ) \int \frac {1}{\left (a^2+a^2 x^2\right )^{5/4}} \, dx}{5 a^2 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \\ & = \frac {2 x}{5 a^4 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x} \left (1+x^2\right )}+\frac {\left (3 \sqrt [4]{1+x^2}\right ) \int \frac {1}{\left (1+x^2\right )^{5/4}} \, dx}{5 a^4 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \\ & = \frac {2 x}{5 a^4 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x} \left (1+x^2\right )}+\frac {6 \sqrt [4]{1+x^2} E\left (\left .\frac {1}{2} \tan ^{-1}(x)\right |2\right )}{5 a^4 \sqrt [4]{a-i a x} \sqrt [4]{a+i a x}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.02 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.80 \[ \int \frac {1}{(a-i a x)^{9/4} (a+i a x)^{9/4}} \, dx=-\frac {i \sqrt [4]{1+i x} \operatorname {Hypergeometric2F1}\left (-\frac {5}{4},\frac {9}{4},-\frac {1}{4},\frac {1}{2}-\frac {i x}{2}\right )}{5 \sqrt [4]{2} a^3 (a-i a x)^{5/4} \sqrt [4]{a+i a x}} \]
[In]
[Out]
\[\int \frac {1}{\left (-i a x +a \right )^{\frac {9}{4}} \left (i a x +a \right )^{\frac {9}{4}}}d x\]
[In]
[Out]
\[ \int \frac {1}{(a-i a x)^{9/4} (a+i a x)^{9/4}} \, dx=\int { \frac {1}{{\left (i \, a x + a\right )}^{\frac {9}{4}} {\left (-i \, a x + a\right )}^{\frac {9}{4}}} \,d x } \]
[In]
[Out]
Time = 85.82 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.08 \[ \int \frac {1}{(a-i a x)^{9/4} (a+i a x)^{9/4}} \, dx=- \frac {i {G_{6, 6}^{5, 3}\left (\begin {matrix} \frac {9}{8}, \frac {13}{8}, 1 & \frac {1}{2}, \frac {9}{4}, \frac {11}{4} \\\frac {9}{8}, \frac {13}{8}, \frac {7}{4}, \frac {9}{4}, \frac {11}{4} & 0 \end {matrix} \middle | {\frac {e^{- 3 i \pi }}{x^{2}}} \right )} e^{\frac {i \pi }{4}}}{4 \pi a^{\frac {9}{2}} \Gamma \left (\frac {9}{4}\right )} + \frac {i {G_{6, 6}^{2, 6}\left (\begin {matrix} - \frac {1}{2}, 0, \frac {1}{2}, \frac {5}{8}, \frac {9}{8}, 1 & \\\frac {5}{8}, \frac {9}{8} & - \frac {1}{2}, 0, \frac {7}{4}, 0 \end {matrix} \middle | {\frac {e^{- i \pi }}{x^{2}}} \right )}}{4 \pi a^{\frac {9}{2}} \Gamma \left (\frac {9}{4}\right )} \]
[In]
[Out]
\[ \int \frac {1}{(a-i a x)^{9/4} (a+i a x)^{9/4}} \, dx=\int { \frac {1}{{\left (i \, a x + a\right )}^{\frac {9}{4}} {\left (-i \, a x + a\right )}^{\frac {9}{4}}} \,d x } \]
[In]
[Out]
Exception generated. \[ \int \frac {1}{(a-i a x)^{9/4} (a+i a x)^{9/4}} \, dx=\text {Exception raised: TypeError} \]
[In]
[Out]
Timed out. \[ \int \frac {1}{(a-i a x)^{9/4} (a+i a x)^{9/4}} \, dx=\int \frac {1}{{\left (a-a\,x\,1{}\mathrm {i}\right )}^{9/4}\,{\left (a+a\,x\,1{}\mathrm {i}\right )}^{9/4}} \,d x \]
[In]
[Out]